5[1+2(x+3)]=6-3(x-1)

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Solution for 5[1+2(x+3)]=6-3(x-1) equation:


Simplifying
5[1 + 2(x + 3)] = 6 + -3(x + -1)

Reorder the terms:
5[1 + 2(3 + x)] = 6 + -3(x + -1)
5[1 + (3 * 2 + x * 2)] = 6 + -3(x + -1)
5[1 + (6 + 2x)] = 6 + -3(x + -1)

Combine like terms: 1 + 6 = 7
5[7 + 2x] = 6 + -3(x + -1)
[7 * 5 + 2x * 5] = 6 + -3(x + -1)
[35 + 10x] = 6 + -3(x + -1)

Reorder the terms:
35 + 10x = 6 + -3(-1 + x)
35 + 10x = 6 + (-1 * -3 + x * -3)
35 + 10x = 6 + (3 + -3x)

Combine like terms: 6 + 3 = 9
35 + 10x = 9 + -3x

Solving
35 + 10x = 9 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.
35 + 10x + 3x = 9 + -3x + 3x

Combine like terms: 10x + 3x = 13x
35 + 13x = 9 + -3x + 3x

Combine like terms: -3x + 3x = 0
35 + 13x = 9 + 0
35 + 13x = 9

Add '-35' to each side of the equation.
35 + -35 + 13x = 9 + -35

Combine like terms: 35 + -35 = 0
0 + 13x = 9 + -35
13x = 9 + -35

Combine like terms: 9 + -35 = -26
13x = -26

Divide each side by '13'.
x = -2

Simplifying
x = -2

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